Return File(ms.ToArray(), 'application/zip', 'Archive.zip') Using (var zipStream = zipArchiveEntry.Open()) zipStream.Write(file2, 0, file2.Length) ZipArchiveEntry = archive.CreateEntry('file2.txt', CompressionLevel.Fastest) Using (var zipStream = zipArchiveEntry.Open()) zipStream.Write(file1, 0, file1.Length) Var zipArchiveEntry = archive.CreateEntry('file1.txt', CompressionLevel.Fastest) Using (var archive = new ZipArchive(ms, ZipArchiveMode.Create, true)) Using (MemoryStream ms = new MemoryStream())

Here’s a quick code sample using a MemoryStream and a couple of byte arrays representing two files: byte file1 = GetFile1ByteArray() NET Framework 4.5 or newer you can avoid third-party libraries and use the System.IO.Compression.ZipArchive native class. OutputStream.Write(buffer, 0, bytesRead) While ((bytesRead = inputStream.Read(buffer, 0, buffer.Length)) != 0) Long bufferSize = inputStream.Length < BUFFER_SIZE ? inputStream.Length : BUFFER_SIZE

Private static void CopyStream(System.IO.FileStream inputStream, System.IO.Stream outputStream) Using (FileStream fileStream = new FileStream(fileToAdd, FileMode.Open, FileAccess.Read)) PackagePart part = zip.CreatePart(uri, '',CompressionOption.Normal) Uri uri = PackUriHelper.CreatePartUri(new Uri(destFilename, UriKind.Relative)) String destFilename = '.\' + Path.GetFileName(fileToAdd) Using (Package zip = System.IO.(zipFilename, FileMode.OpenOrCreate)) Private static void AddFileToZip(string zipFilename, string fileToAdd) using System ĪddFileToZip('Output.zip', const long BUFFER_SIZE = 4096 The link isn't stable, so here's the example Jon provided in the post. Here's a blog post with an example (its at the end dig for it). System.IO.Packaging has classes that can be used to drop content into a zip file. You don't have to use an external library anymore.

Creating a zip file in microsoft 2010